3b^2-37b+90=0

Solution for 3b^2-37b+90=0 equation:

3b^2-37b+90=0

a = 3; b = -37; c = +90;
Δ = b2-4ac
Δ = -372-4·3·90
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-17}{2*3}=\frac{20}{6}
=3+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+17}{2*3}=\frac{54}{6}
=9
$